[LectronFanModerator]

Hi all,

Here’s a little simple circuit that indicates for a brief moment that power is applied to a circuit.
This will reduce current as the indicator is only lit for a few seconds.
In version V1 we will use the light bulb and the modern Lectron set.
Since this is a fun and useful circuit we will enhance it a little further.
We will also use the legacy set with Ge transistors in later versions.
Who can explain what happens when you press and release the switch ?
Hint : there’s a feedback loop, can you spot it ?

Many greetings

[MichaelKeymaster]

Hi Frank,

Thanks so much for another circuit for fellow Lectroneers to enjoy!

The T2 sub circuit as the loopback?

[LectronFanModerator]

Hi all !
As you noticed well Michael, T2 plays an important role in the feedback loop.
Can you try to figure out what it does ?

In the meanwhile, here is the same circuit but made with the legacy parts.
Don’t forget that this circuit uses a positive GND, so mount C1 and the battery accordingly !
R2 is changed into 4,7K to make it work.
Do you think that we can swap T1 & T2 ?
Remeber that the legacy transistors have a build in resistor which influence the bias of the transistors !
Many greetings

[Author]

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