Well folks, what we have here is a circuit that can be found in our house.
We have a large corridor with only 1 light bulb and 3 switches located at different spots.
It is obvious that each switch can turn the lamp either on or either off.
This can be simulated with our Lectron set
Our Lectron circuit is a little bit different in the fact that we have only SPDT (Single Pole Double Throw) switches.
To make the situation work we are using the relay who’s has DPDT switches.
Your truth table is correct, but let’s assume this :
Switch Nr1 UP = 1 and down = 0
Switch Nr2 LEFT = 0 and RIGHT = 1
Switch Nr3 UP = 0 and DOWN = 1
We would have a truth table like this :
So in short, the light bulb will only lit when an uneven count of switch positions will be on.
In your table, A and B are the 2 inputs of an EX OR gate.
In our example, we would have A, B and C since we have a 3 input EX OR gate.
Greetings
- This reply was modified 4 years, 5 months ago by Michael. Reason: Changed font and size styling for easier reading
- This reply was modified 4 years, 5 months ago by LectronFan.
- This reply was modified 4 years, 5 months ago by LectronFan. Reason: Table not correct