[LectronFanModerator]

<p style=”text-align: left;”>Hi all !</p>
The solution of the capacitor is as follows :

At first, C1 is completely discharged.

When pressing S1 and S3, C1 starts to charge very quickly through the relay coil and T1.
This means that a brief high current will flow the relay coil (capacitor property).
This high current causes the relay to be activated and the lamp turns on.

As soon C1 is charged, this high current stops but the relay will still be energised through the lower current flowing through R2 (the relay needs less current to be in the hold position).

Noticed how we used T1 as an emitter follower to adjust the current through the relay circuit ?

Many greetings